Question

find the tangent to the curve given by the parametric equations:
x=1/t y=sqrt(t)e^(-t)

Answer 1

dy/dx = (dy/dt) / (dx/dt) = [(1-2t)e^-t / 2√t] / (-1/t^2)

= (2t-1)/2 t^(3/2) e^-t