Asked by helppls
find the tangent to the curve given by the parametric equations:
x=1/t y=sqrt(t)e^(-t)
x=1/t y=sqrt(t)e^(-t)
Answers
Answered by
oobleck
dy/dx = (dy/dt) / (dx/dt) = [(1-2t)e^-t / 2√t] / (-1/t^2)
= (2t-1)/2 t^(3/2) e^-t
= (2t-1)/2 t^(3/2) e^-t
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