Asked by Anon

Consider the following data.

DeltaHf (Na2O (s))=-414kJ/mol

Delta H sublimation(Na)=109 kJ/mol

I.E. (Na)=495 kJ/mol

Bond Energy (O2) = 495 kJ/mol

E.A. (O) = -141 kJ/mol

E.A. (O -) = 878 kJ/mol

Use this information to calculate the lattice energy of Na2O (s).
So, we have the total which is delta H f (-414kJ/mol) and delta Hf= Delta H1+deltaH2+,...,+x
Where x is the lattice energy. I am still struggling in finding x

Answers

Answered by Dave
Is this AP Chem or regular chem?
Answered by Anonymous
45
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