Asked by Christian
What is Delta H degrees for the gas-phase reaction below?
CH4+ CL3 = CH3CL+ HCL
Bond dissociation energies of CL-CL, C-CL, H-CL, and H-C are 243, 339, 431, and 414kj/mol respectively
a)113kJ
b)-113kJ
c)263kJ
d)-263kJ
Can somebody teach me how to solve this?
CH4+ CL3 = CH3CL+ HCL
Bond dissociation energies of CL-CL, C-CL, H-CL, and H-C are 243, 339, 431, and 414kj/mol respectively
a)113kJ
b)-113kJ
c)263kJ
d)-263kJ
Can somebody teach me how to solve this?
Answers
Answered by
DrBob222
B.E. = bond energy.
delta Hrxn = (sum B.E.reactants)-(sum B.E. products)
DErxn = [DE(C-H) + DE(Cl-Cl)] -[DE(C-Cl) + DE(H-Cl)] = ??
If I didn't goof the value is -113 kJ/mol but check me out on that.This procedure is good ONLY for estimating delta Hrxn and it is good for gas phase reactions only. The better value is obtained by looking up delta H formations and DErxn = (sum products)-(sum reactants) [<b>Note the difference between the two procedures. From BE it is (sum reactants)- (sum products) and from DHformation it is (sum products) - (sum reactants).</b>
delta Hrxn = (sum B.E.reactants)-(sum B.E. products)
DErxn = [DE(C-H) + DE(Cl-Cl)] -[DE(C-Cl) + DE(H-Cl)] = ??
If I didn't goof the value is -113 kJ/mol but check me out on that.This procedure is good ONLY for estimating delta Hrxn and it is good for gas phase reactions only. The better value is obtained by looking up delta H formations and DErxn = (sum products)-(sum reactants) [<b>Note the difference between the two procedures. From BE it is (sum reactants)- (sum products) and from DHformation it is (sum products) - (sum reactants).</b>
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