Asked by Anonymous
A sample of 0.250 g of nickel complex was titrated with 0.150 M EDTA. If the titration of the nickel sample required 7.5 mL of EDTA to reach the equivalence point, what is the percent nickel in the sample?
Answers
Answered by
DrBob222
Ni^2+ + 2EDTA ==> Ni(EDTA)2
mols EDTA - 0.0075 x 0.15 = ?
mols Ni = 1/2 that
g Ni = mols Ni x atomic mass Ni = ?
%yield = (g Ni/mass sample)*100 = ?
mols EDTA - 0.0075 x 0.15 = ?
mols Ni = 1/2 that
g Ni = mols Ni x atomic mass Ni = ?
%yield = (g Ni/mass sample)*100 = ?
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