Asked by lizzie
2.241g sample of nickel reacts w oxygen to form 2.85g of the metal oxide. Calculate the empirical formula of the oxide?
Answers
Answered by
DrBob222
Convert 2.241 g Ni to mols.
Determine mass oxygen fron mass metal oxide - mass metal = mass oxygen.
Convert g oxygen to mols oxygen ATOMS.
Deterime ratio of atoms. Those will be the subscripts. Post your work if you get stuck.
Determine mass oxygen fron mass metal oxide - mass metal = mass oxygen.
Convert g oxygen to mols oxygen ATOMS.
Deterime ratio of atoms. Those will be the subscripts. Post your work if you get stuck.
Answered by
lizzie
n= 2.241/14.00=.1600
.1600/.0382=4.189
o=.611/16.00= .0382
.0382/.0382=0
I cant seem to get a whole # for the nickel
.1600/.0382=4.189
o=.611/16.00= .0382
.0382/.0382=0
I cant seem to get a whole # for the nickel
Answered by
DrBob222
Nickel is Ni. You are using N = 14.00
Not the same thing.
Not the same thing.
Answered by
lizzie
i looked up the wronge symbol. the answer i got was NiO
Answered by
DrBob222
NiO is correct.
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