(x-1+i)(x-2)=0
multiply it out, and gather terms.
how do you write simples polynomial function with the given zero
1-i and 2
2 answers
However, if you want a polynomial with real coefficients, you need another zero: the conjugate of 1-i = 1+i
SO, your polynomial is then
(x-(1-i))(x-(1+i))(x-2)
((x-1)+i)((x-1)-i)(x-2)
((x-1)^2+1)(x-2)
(x^2-2x+2)(x-2)
...
SO, your polynomial is then
(x-(1-i))(x-(1+i))(x-2)
((x-1)+i)((x-1)-i)(x-2)
((x-1)^2+1)(x-2)
(x^2-2x+2)(x-2)
...