Asked by Anonymous
What volume of oxygen gas at 20.9 c and 750 torr is needed to burn 3.00 liters of propane, C3H8 at the same temprrature and pressure?
I know i use V1/n1=V2/n2, but how do i get n?
I know i use V1/n1=V2/n2, but how do i get n?
Answers
Answered by
bobpursley
write the reaction first.
C3H8 + 5O2 >> 3CO2 + 4H2O
so you need five times the volume of O2, looks like 15 liters.
Remember, in gases, at the same temp, pressure, contain the same number of moles per volume. Gay-Lussac's law of combining volumes applies
C3H8 + 5O2 >> 3CO2 + 4H2O
so you need five times the volume of O2, looks like 15 liters.
Remember, in gases, at the same temp, pressure, contain the same number of moles per volume. Gay-Lussac's law of combining volumes applies
Answered by
Anonymous
Thank you this helped clearify things
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