Asked by Robert
Calculate the solubility (in g/L) of calcium fluoride in water at 25°C if the Ksp for is 1.5 × 10-10 .
Answers
Answered by
bobpursley
CaF2 <>Ca + 2 F
let x represent solubility
ksp=x*(2x)^2
4x^3=Ksp
solve for x, which is in moles per liter.
now convert moles x to grams of CAF2 It should be on the order of .02grams/liter
lets see
solubility= x*molmass= cubrt(1.5E-10 /4)=.026grams/liter
let x represent solubility
ksp=x*(2x)^2
4x^3=Ksp
solve for x, which is in moles per liter.
now convert moles x to grams of CAF2 It should be on the order of .02grams/liter
lets see
solubility= x*molmass= cubrt(1.5E-10 /4)=.026grams/liter