Asked by Robert

Calculate the solubility (in g/L) of calcium fluoride in water at 25°C if the Ksp for is 1.5 × 10-10 .

Answers

Answered by bobpursley
CaF2 <>Ca + 2 F

let x represent solubility
ksp=x*(2x)^2

4x^3=Ksp
solve for x, which is in moles per liter.

now convert moles x to grams of CAF2 It should be on the order of .02grams/liter

lets see
solubility= x*molmass= cubrt(1.5E-10 /4)=.026grams/liter
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