Asked by Kathy
what is the molar concentration of h2so4 solution is 2.0ml of which is completely neutralized by 45.0ml of 0.115 mol/L NaOH solution?
Answers
Answered by
DrBob222
H2SO4 + 2NaOH ==> 2H2O + Na2SO4
mols NaOH = M x L = ?
Note that mols H2SO4 = 1/2 mols NaOH
Then M H2SO4 = mols H2SO4/L H2SO4.
mols NaOH = M x L = ?
Note that mols H2SO4 = 1/2 mols NaOH
Then M H2SO4 = mols H2SO4/L H2SO4.
Answered by
laila
1.293 mol/L
Answered by
DrBob222
It's 1.2937 but note that you're allowed only two significant figures (limited by the 2.0 mL) so that would round to 1.3 M.
Answered by
Kay
H2SO4 + 2 NaOH = 2 H2O + Na2SO4
V H2SO4 = 0.025L since you divide it by 1000 to get L
C H2SO4= ?
V NaOH = 0.045L
C NaOH = 0.115
First find the moles for NaOH to find moles you do n= C*V
n= 0.115*0.045
n= 0.005175
Now do molar ratios
H2SO4 1 x
-------- = --- = ---------
NaOH 2 0.005175
x= 1*0.005175
----------
2
x= 0.025875
That is number of H2SO4 moles
now final step find the concentration
C= n/v
C= 0.025875
----------
0.025
C= 1.035 mol/L
therefore the answer is 1.035 mol/L
V H2SO4 = 0.025L since you divide it by 1000 to get L
C H2SO4= ?
V NaOH = 0.045L
C NaOH = 0.115
First find the moles for NaOH to find moles you do n= C*V
n= 0.115*0.045
n= 0.005175
Now do molar ratios
H2SO4 1 x
-------- = --- = ---------
NaOH 2 0.005175
x= 1*0.005175
----------
2
x= 0.025875
That is number of H2SO4 moles
now final step find the concentration
C= n/v
C= 0.025875
----------
0.025
C= 1.035 mol/L
therefore the answer is 1.035 mol/L
Answered by
Kathy
Hey guys thank you but I just realized that the question is suppose to be 25.0mL not 2.0 my keyboard messed it up. Thanks for all your help but i figured the answer right above this is mine can you just tell me if that's right or wrong?
Answered by
Kathy
my final answer is 1.035 mol/L
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