Asked by lanorris

How many milliliters of an aqueous solution of 0.165 M aluminum chloride is needed to obtain 13.2 grams of the salt?
Answered by DrBob222
Convert 13.2 g AlCl3 to mols. mols = grams/molar mass = ?

Then M = mols/L solution. You know mols and M, solve for L and convert to mL.
Answered by laila
599,9 mL
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