Asked by jhon
a 20 kg traveler's bag is being pulled along the floor with a force of 50 NF. the force is applied on the handle forming an angle of 30 degree with the horizontal. neglecting friction,what is the acceleration og the bag? How much force is exerted by the floor on the bag?
Answers
Answered by
Henry
M*g = 20 * 9.8 = 196 N.=Wt. of suitcase.
a. a = Fx/M = 50*cos30/20 = 2.17 m/s^2.
b. Fn = 196 - 50*sin30 = 171 N.=Normal
force = Force exerted on the bag by the
floor.
a. a = Fx/M = 50*cos30/20 = 2.17 m/s^2.
b. Fn = 196 - 50*sin30 = 171 N.=Normal
force = Force exerted on the bag by the
floor.
Answered by
jerick junio
NONE
Answered by
jerick junio
2.17 m/s^2
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