Asked by Anonymous


A traveler pulls on a suitcase strap at an angle 36 above the horizontal. If 555 J of work are done by the strap while moving the suitcase a horizontal distance of 15 m, what is the tension in the strap?
Answered by Anonymous
A traveler pulls on a suitcase strap at an angle 36 above the horizontal. If 555 J of work are done by the strap while moving the suitcase a horizontal distance of 15 m, what is the tension in the strap?
Answered by Henry
Work = Fap*Cos A * d = 555 J.
Fap*Cos36 * 15 = 555
12.14*Fap = 555
Fap = 45.7 N. = Force applied. = Tension
in the strap.
Answered by Anonymous
46 N
Answered by Cool
W=Fdcos(theta)
W=555J
d=15m
theta=36 degree
F=W/(dcos(theta))
F=555J/(15m*cos36)
F=46N