Asked by takunda
Find the taylor polynomial of degree 3 for f(x)=1/x+2
F(x)=-1/x+2)
F(x)=-1/x+2)
Answers
Answered by
Steve
well,
f = 1/(x+2)
f' = -1(x+2)^2
f" = 2/(x+2)^3
f<sup>(3)</sup> = -6/(x+3)^4
So, the Taylor series at x=0 is
1/2 - x/4 + x^2/8 - x^3/16 + ...
f = 1/(x+2)
f' = -1(x+2)^2
f" = 2/(x+2)^3
f<sup>(3)</sup> = -6/(x+3)^4
So, the Taylor series at x=0 is
1/2 - x/4 + x^2/8 - x^3/16 + ...
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