Question

To make a phosphorus fertilizer, agricultural companies use the following reaction:
Ca3P2O8 + 2H2SO4 --> CaH4P2O8 + 2CaH4SO6
(fertilizer)
If 1.50 * 10^4 grams of H2SO4 are reacted with excess Ca3P2O8 and H2O, how many grams of fertilizer can be made?

Hi, I pretty much get what the problem is asking, but I'm getting confused on what to do with the two excess compounds,Ca3P2O8 and H2O, because I've only worked on problems with one compound. It would be great if someone could explain what I should do. -- Thank you.

Answer 1

You just ignore the excess compounds.
all that is important here is for every 2 mols of H2SO4 you get one mol of CaH4P2O8

Answer 2

MY FEED BACK PLEASE