Question

A 30% solution of fertilizer is to be mixed with a 60% solution of fertilizer in order to get 150 gallons of 50% solution. How many gallons of the 30% and the 60% solutions should be mixed. I really need help.

Answer 1

x = gal of 30% solution
.30x = value of 30% solution
150 - x = gal of 60% solution
.60(150 - x)
.50(150) = mixture

.30x + .60(150 - x) = .50(150)

Solve for x, gal of 30% solution
150 - x = gal of 60% solution