Question
The two equal sides of an isosceles triangle are each 24 centimeters. If each of the two equal angles measures 60, find the length of the base and the altitude. (leave your answer in radical form).
Answers
Damon
LOL, but if two angles are 60 then so is the third and it is an equilateral triangle :)
base = 24
12^2 + h^2 = 24^2
h^2 = -(3*4)^2 + (6 *4)^2
h^2 = 4^2 ( -9+36) = 4^2 (27) = 4^2*3^3
h = 4*3 * sqrt 3
h = 12 sqrt 3
base = 24
12^2 + h^2 = 24^2
h^2 = -(3*4)^2 + (6 *4)^2
h^2 = 4^2 ( -9+36) = 4^2 (27) = 4^2*3^3
h = 4*3 * sqrt 3
h = 12 sqrt 3