Question

A student fires a rocket at 24 degrees above the horizontal. The 10kg rocket comes out of the gun barrel at 1000 m/s, and accelerates 15 m/s^2 uniformly until it burns out 2 seconds later. It then is acted apon by gravity until it hits the ground. I need to see a drawn out picture of this.

Answer 1

Vo = 1000m/s[24o]
Xo = 1000*Cos24 = 913.5 m/s.
Yo = 1000*sin24 = 406.7 m/s.

h1=Yo*t + 0.5a*t^2=406.7*2 + 7.5*2^2 =
843.4 m
Y1 = Yo + a*t = 406.7 + 15*2=436.7 m/s.

Y2 = Y1 + g*t = 0 @ max ht.
t = -Y1/g = -436.7/-9.8 = 44.56 s.
Tr = t+2 = 44.56 + 2 = 46.56 s. =
Rise time or time to reach max ht.

h max = h1 + -(Y1^2)/2g
h max=843.4 + -(436.7^2)/-19.6=10,573 m
Above gnd.
h = 0.5g*t^2 = 10,573 m.
4.9t^2 = 10,573
t^2 = 2158
Tf = 46.45 s. = Fall time.

T = Tr+Tf = 46.56 + 46.45 = 93 s. = Time in flight.

Range = Xo*T = 913.5m/s * 93s.=84,966 m.