mols ethylene glycol = grams/molar mass = ?
Then m = molality = mols/kg solvent (kg solvent is 0.0854 in the problem)
The formula are similar for f.p. and b.p.
f.p. delta T = Kf*m. Substitute and solve for delta T, then subtract from the normal f.p. of O C to find the new f.p.
b.p. delta T = Kb*m. Substitute and solve for delta T and add to the normal point point of water which is 100 C to find the new boiling point.
Post your work if you get stuck.
An ethylene glycol solution contains 18.2g of ethylene glycol (C2H6O2) in 85.4mL of water.
Calculate the freezing point and boiling point of the solution. (Assume a density of 1.00 g/mL for water.)
3 answers
I figured it out! Thank you so much, I really do appreciate it.
what's the answer
4 answers