Asked by Angel
An aqueous antifreeze is 40.0% ethylene glycol (C2H6O2) by mass. The density of the solution is 1.05 g/cm3. Calculate the molality, molarity, and mole fraction of the ethylene glycol.
Answers
Answered by
DrBob222
A long problem here. You can help by telling me what you don't understand about it before I spent half the night working all of it out in detail.
I'll get you started.
40% by mass means 40 g ethylene glycol + 60 g water.
Convert 40 g ethylene glycol to moles. moles = grams/molar mass.
molality = moles/kg solvent(60 g water = 0.060 kg).
For molarity, use mols/L of solution.
Look up mole fraction.
That's X<sub>eth gly</sub> = (n<sub>eth gly</sub>/total moles.
I'll get you started.
40% by mass means 40 g ethylene glycol + 60 g water.
Convert 40 g ethylene glycol to moles. moles = grams/molar mass.
molality = moles/kg solvent(60 g water = 0.060 kg).
For molarity, use mols/L of solution.
Look up mole fraction.
That's X<sub>eth gly</sub> = (n<sub>eth gly</sub>/total moles.
Answered by
soofiyanatar
6.77M
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