Asked by brenn
When 1.375g CaO is added to 50 mL water at 25.0 degree C, the temperature of the water increases to 34.6 degree C. Given the specific heat is 4.184 j/g*degree C, how much heat is absorbed by the calorimeter?
Answers
Answered by
DrBob222
q = mass H2O x specific heat H2O x (Tfinal-Tinitial) is the heat absorbed.
Then q/1.375 is heat absorbed per gram CaO and that x molar mass CaO is heat absorbed per mol CaO. I think those questions would follow although you didn't post them yet.
Then q/1.375 is heat absorbed per gram CaO and that x molar mass CaO is heat absorbed per mol CaO. I think those questions would follow although you didn't post them yet.
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