Question
If 100 ml of water at 60 degree is added to 200 ml of water at 30 degree then the temperature in mixture is options A) 45 degree B) 40 degree C) 50 degree
Answers
Nonetheless
Heat lost = Heat gained
Let x be the final temperature of the mixture.
(100)(60 - x)(4.184)=(200)(x - 30)(4.184)
Solve for x
Let x be the final temperature of the mixture.
(100)(60 - x)(4.184)=(200)(x - 30)(4.184)
Solve for x
Srujana Meda
Temp in mixture =M1t1+m2t2/m1+m2
100*60+200*30/100+200=
6000+6000 /300=
12000/300=
40
Hence,40 is the temperature in mixture.
Hope this helps you.
100*60+200*30/100+200=
6000+6000 /300=
12000/300=
40
Hence,40 is the temperature in mixture.
Hope this helps you.