Asked by Frank

A ball is thrown horizontally from the top of a building 45.9 m high. The ball strikes the ground at a point 121 m from the base of the building.
The acceleration of gravity is 9.8 m/s2 . Find the time the ball is in motion. Answer in units of s

Find the initial velocity of the ball. Answer in units of m/s

Find the x component of its velocity just be- fore it strikes the ground.
Answer in units of m/s

Find the y component of its velocity just be- fore it strikes the ground.
Answer in units of m/s
Answered by Steve
Find the time to hit using

4.9t^2 = 45.9

Plug that t into get Vx

Vx = 121/t
Vx does not change

Vy = -9.8t
Answered by Frank
I don't get it
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