Find the time to hit using
4.9t^2 = 45.9
Plug that t into get Vx
Vx = 121/t
Vx does not change
Vy = -9.8t
A ball is thrown horizontally from the top of a building 45.9 m high. The ball strikes the ground at a point 121 m from the base of the building.
The acceleration of gravity is 9.8 m/s2 . Find the time the ball is in motion. Answer in units of s
Find the initial velocity of the ball. Answer in units of m/s
Find the x component of its velocity just be- fore it strikes the ground.
Answer in units of m/s
Find the y component of its velocity just be- fore it strikes the ground.
Answer in units of m/s
2 answers
I don't get it
2 answers