Asked by Persia
                WHAT IS THE MOLARITY OF A SOLUTION PREPARED BY DISSLOVING 4.92 GRAMS OF CALCIUM NITRATE, Ca(NO3)2 in 250 mL OF WATER?
            
            
        Answers
                    Answered by
            DrBob222
            
    Remember the definition.
M = #mols/L.
# mols = grams/molar mass.
Post your work if you get stuck.
    
M = #mols/L.
# mols = grams/molar mass.
Post your work if you get stuck.
                    Answered by
            Persia
            
    Dr. Bob222 I'm not following. Would you please further explain?
Thanks
    
Thanks
                    Answered by
            DrBob222
            
    Plug in the numbers.
# mols = g/molar mass = 4.92/molar mass Ca(NO3)2 = xx mols Ca(NO3)2.
Then M = #mols/L = xxmols/0.250 L = ?? M.
    
# mols = g/molar mass = 4.92/molar mass Ca(NO3)2 = xx mols Ca(NO3)2.
Then M = #mols/L = xxmols/0.250 L = ?? M.
                    Answered by
            DrBob222
            
    Technically, the problem should have said in 250 mL of SOLUTION. There is a difference. Or the problem could have said dissolve in a little water and make to a final volume of 250 mL.  Or they could have asked for the molality and given the density and calculated the molarity that way; however, I think, in the spirit of the problem that it means 250 mL solution. 
    
                                                    There are no AI answers yet. The ability to request AI answers is coming soon!
                                            
                Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.