Asked by Jessica
The maker of an automobile advertises that it takes 11 seconds to accelerate from 15 kilometers per hour to 90 kilometers per hour. Assuming constant acceleration, compute the following.
What is the distance the car travels during the 11 seconds (Round your answer to two decimal places.)?
What is the distance the car travels during the 11 seconds (Round your answer to two decimal places.)?
Answers
Answered by
Steve
a = 75 km/hr/s
= 20.833 m/s^2
s = vt + 1/2 at^2 = 4.1667(11) + (1/2)(20.833)(11^2) = 1306.23 m
= 20.833 m/s^2
s = vt + 1/2 at^2 = 4.1667(11) + (1/2)(20.833)(11^2) = 1306.23 m
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