Asked by Anon

How many liters of CO2 gas are contained in a 3.16 liters of a gas mixture which is 8.1% (v/v) CO2?

They never gave us the formula or a process to figure this out in class. Will you please help?
Answered by DrBob222
The usual formula for %v/v is (volume gas/total volume)*100 = %.

(x L CO2/3.16L)*100 = 8.1%
Solve for x L CO2.
Answered by Anon
Would the answer be .25596?

8.1/100= .081

.081*3.16= .25596
Answered by DrBob222
Yes but if your prof is picky about the number of significant figures you will get marked down. You're allowed 2 places (because of the 8.1 so you should round that number fo 0.26 AND place a unit on it of L.
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