Asked by jacky
We did not find results for: a conical tank with its vertex down is 12 feet high and 12 feet in diameter at the top. water is being pumped in at the rate of 8 feet cubed per minute. find the rate at which the water level is rising when the water is 4 feet deep.
Answers
Answered by
Steve
at any depth y, the radius of the surface of the water is y/2. So,
v = pi/3 (y/2)^2 y
= pi/12 y^3
dv/dt = pi/4 y^2 dy/dt
Now plug in your numbers.
v = pi/3 (y/2)^2 y
= pi/12 y^3
dv/dt = pi/4 y^2 dy/dt
Now plug in your numbers.
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