Asked by Anonymous
Identify the extrema for the function. Classify it as a relative (local) or absolute (global) maximum or minimum value.
f(x)=4x^3-12x^2+15
f(x)=4x^3-12x^2+15
Answers
Answered by
Steve
extrema where
12x^2 - 24x = 0
12x(x-2) = 0
Now apply the 2nd derivative test, and what you know about the general shape of cubics.
12x^2 - 24x = 0
12x(x-2) = 0
Now apply the 2nd derivative test, and what you know about the general shape of cubics.
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