Asked by Anonymous
Find all points of extrema on the interval [0, 2pi] if y=x+sinx
(-1.-1+(3pi/2))
(pi, pi)
(-1,0)
((3pi/2), 0)
none of these
I got pi as my critical number but I'm confused with the intervals.
(-1.-1+(3pi/2))
(pi, pi)
(-1,0)
((3pi/2), 0)
none of these
I got pi as my critical number but I'm confused with the intervals.
Answers
Answered by
Reiny
dy/dx = 1 + cosx
= 0
cosx = -1
look at your cosine curve.
There is only one place where it has a value of -1 and it is at 180° or π radians for its entire period from 0 to 2π
so when x = π , back in the original equation:
y = π + sinπ
= π + 0 = π
so the point is (π,π)
= 0
cosx = -1
look at your cosine curve.
There is only one place where it has a value of -1 and it is at 180° or π radians for its entire period from 0 to 2π
so when x = π , back in the original equation:
y = π + sinπ
= π + 0 = π
so the point is (π,π)
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