Asked by Morgan
Use the derivative of f(x) = 6x7 + 7x6 to determine any points on the graph of f(x) at which the tangent line is horizontal.
Answers
Answered by
Steve
f(x) = 6x^7 + 7x^6
f'(x) = 42x^6 + 42x^5
= 42x^5(x+1)
so, now it's easy to see where f'(x) = 0
f'(x) = 42x^6 + 42x^5
= 42x^5(x+1)
so, now it's easy to see where f'(x) = 0
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