Asked by Juan
A box weighing 178N slides down a ramp with an initial velocity of 0.5m/s^2. The ramp has an angle of 24 degrees and is 3m long. What is the acceleration of the box? I know that F=ma but how do I find a?
Answers
Answered by
Henry
M*g = 178 N.
Vo = 0.5 m/s.
Ramp = 3m[24o]
Fp = 178*sin24 = 72.4 N. = Force parallel to the ramp.
M*g = 178
M = 178/g = 178/9.8 = 18.16 kg = mass of box.
a = Fp/M = 72.4/18.16 = 3.99 m/s^2.
Vo = 0.5 m/s.
Ramp = 3m[24o]
Fp = 178*sin24 = 72.4 N. = Force parallel to the ramp.
M*g = 178
M = 178/g = 178/9.8 = 18.16 kg = mass of box.
a = Fp/M = 72.4/18.16 = 3.99 m/s^2.
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