Asked by Anonymous
An airplane approaches an airport. At a certain time, it is 939 m high. Its angle of elevation measured from the airport is 19.5◦. To the nearest metre, how far is the plane from the airport?
Answers
Answered by
Reiny
if you want the direct line distance (along the hypotenuse)
sin 19.5 = 939/d
d = 939/sin19.5 = 2813 m
If you want the horizontal displacement
tan 19.5 = 939/x
x = 939/tan19.5 = 2652 m to the nearest metre
sin 19.5 = 939/d
d = 939/sin19.5 = 2813 m
If you want the horizontal displacement
tan 19.5 = 939/x
x = 939/tan19.5 = 2652 m to the nearest metre
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