Asked by Kay
A penny on its side moving at speed v slides off the horizontal surface of a table a vertical distance y from the floor.
a) Show that the penny lands a distance v√(2y/g) from the base of the coffee table.
b) If the speed is 3.5 m/s and the coffee table is 0.4 m tall, show that the distance the coin lands from the base of the table is 1.0 m. (Use g = 9.8 m/s^2)
a) Show that the penny lands a distance v√(2y/g) from the base of the coffee table.
b) If the speed is 3.5 m/s and the coffee table is 0.4 m tall, show that the distance the coin lands from the base of the table is 1.0 m. (Use g = 9.8 m/s^2)
Answers
Answered by
bobpursley
time in air:
y=1/2 g t^2
t=sqrt(2y/g)
horizonal distance=vt=vsqrt(2y/g)
y=1/2 g t^2
t=sqrt(2y/g)
horizonal distance=vt=vsqrt(2y/g)
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