Asked by Mercury
Power supplied to a particle of mass 2 Kg varies with time as p = 3t^2/2 watt. Here t is in seconds. If initial velocity = 0, find the velocity after 2s.
Sorry for not proving my work. Frankly speaking I'm unable to solve any power questions. Any help would be appreciated. :)
Sorry for not proving my work. Frankly speaking I'm unable to solve any power questions. Any help would be appreciated. :)
Answers
Answered by
bobpursley
Final ke= Integral power*dt
1/2 m v^2=INT 3t^2/2 dt
= t^3/2 over limits from t=0 to 2
1/2 mv^2=4
v=2 m/s
check that.
1/2 m v^2=INT 3t^2/2 dt
= t^3/2 over limits from t=0 to 2
1/2 mv^2=4
v=2 m/s
check that.
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