Asked by Gary
If ∆Q is the heat supplied to a gas so that the internal energy of the system increases by ∆U, then the work done ∆W by the gas is equal to:
∆Q – ∆U
∆Q + ∆U
∆Q x ∆U
∆U/∆Q
∆Q – ∆U
∆Q + ∆U
∆Q x ∆U
∆U/∆Q
Answers
Answered by
Anonymous
∆Q – ∆U
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