Asked by Callie
A student mixed two clear liquids together in a beaker and a solid precipitate formed. His data is shown in the table below.
Liquid reactant A = 10 g
Liquid reactant B = 17 g
Beaker + solid product= 32 g
What is the mass of the beaker?
A. 5 g
B. 10 g
C. 15 g
D. 17 g
E. 32 g
Is the answer E?
Thank you
Liquid reactant A = 10 g
Liquid reactant B = 17 g
Beaker + solid product= 32 g
What is the mass of the beaker?
A. 5 g
B. 10 g
C. 15 g
D. 17 g
E. 32 g
Is the answer E?
Thank you
Answers
Answered by
David
Due to the conservation of mass, the mass of the reactants is equal to the mass of the products.
Mass(A) + Mass(B) = Mass Solid Product
10g + 17g = 27g
Mass(beaker) = Mass(Beaker + product) - Mass (product)
So Mass(Beaker) = 32g - 27g = 5g
So your answer is "A. 5g."
Mass(A) + Mass(B) = Mass Solid Product
10g + 17g = 27g
Mass(beaker) = Mass(Beaker + product) - Mass (product)
So Mass(Beaker) = 32g - 27g = 5g
So your answer is "A. 5g."
Answered by
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