Question

How many square units are in the area of the triangle whose vertices are the x and y intercepts of the cuure
y=(x-3)^2(x+2)?

Answer 1

So we are going to need those intercepts,
the x - intercepts are easy
x = 3 or x = -2
for the y-intercept, let x = 0
y = (-3)^2 (2) = 18

so the points of the triangle are (3,0), (-2,0) and (0,18)
so the base of the triangle is 5
and the height is 18

area = (1/2)(base)(height)
= (1/2)(5)(18) = 45 square units