Question
determine the percent yield when 5.00g benzene burns in oxygen gas to form 1.50g of carbon dioxide and water vapor.
Answers
DrBob222
2C6H6 + 15O2 ==> 12CO2 + 6H2O
mols benzene = grams/molar mass
Using the coefficients in the balanced equation, convert mols benzene to mols CO2.
Convert mols H2O to grams H2O with g = mols x molar mass. This is the theoretical yield (TY). The actual yield (AY) in the problem is 1.50g.
%yield = (AY/TY)*100 = ?
mols benzene = grams/molar mass
Using the coefficients in the balanced equation, convert mols benzene to mols CO2.
Convert mols H2O to grams H2O with g = mols x molar mass. This is the theoretical yield (TY). The actual yield (AY) in the problem is 1.50g.
%yield = (AY/TY)*100 = ?