Asked by Babydoll07
Can someone please explain why (-9)1/2 is not a real number but -9 1/2 is a real number
Answers
Answered by
Reiny
This only makes sense if you meant
√(-9) vs - (√9)
remember we cannot take the square root of a negative number, that would be an imaginary or complex answer.
but by the order of operation for -√9
we take the square root first, and then make the answer negative, so
- √9 = -3
√(-9) vs - (√9)
remember we cannot take the square root of a negative number, that would be an imaginary or complex answer.
but by the order of operation for -√9
we take the square root first, and then make the answer negative, so
- √9 = -3
Answered by
Babydoll07
So are you saying that (-9)1/2 and
-9 1/2 is not a real number because that is how the problem was written
-9 1/2 is not a real number because that is how the problem was written
Answered by
Reiny
I assumed that you meant
(-9)^(1/2)
which is the same as √-9 , which of course is not real
vs
-(9^(1/2))
which is -√9
which is -3
the ^ is the generally accepted symbol to indicate an exponent,
e.g. x^2 is x squared, x^5 is x to the fifth, etc
(-9)^(1/2)
which is the same as √-9 , which of course is not real
vs
-(9^(1/2))
which is -√9
which is -3
the ^ is the generally accepted symbol to indicate an exponent,
e.g. x^2 is x squared, x^5 is x to the fifth, etc
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