Asked by Jason
1.71 kg of glass (ρ = 2.66 x 10^3 kg/m3) is shaped into a hollow spherical shell that just barely floats in water. What are the (a) outer and (b) inner radii of the shell? Do not assume the shell is thin.
Volume = 2.66 * 10^3/1.71
V=1555.56 m^3
V=pi(r^2)h
Volume = 2.66 * 10^3/1.71
V=1555.56 m^3
V=pi(r^2)h
Answers
Answered by
Damon
Volume of Glass = (4/3) pi (Ro^3 - Ri^3)
mass of glass = rho V
so
1.71 = 2660 (4/3) pi (Ro^3-Ri^3)
so
(Ro^3 - Ri^3) = 4.8214*10^-4
Now Archimedes assume rho water = 1000
1000 (4/3)pi Ro^3 = 1.71
solve for Ro^3
go back and get Ri^3
take cube roots :)
mass of glass = rho V
so
1.71 = 2660 (4/3) pi (Ro^3-Ri^3)
so
(Ro^3 - Ri^3) = 4.8214*10^-4
Now Archimedes assume rho water = 1000
1000 (4/3)pi Ro^3 = 1.71
solve for Ro^3
go back and get Ri^3
take cube roots :)
Answered by
Damon
By the way, your formula is for the volume of a cylinder, not a sphere. Use (4/3)pi r^3
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