Question
Find the slope of the tangent line to the graph of the given function at the given value of x.
y=-5x^1/2+x^3/2; x=25
y=-5x^1/2+x^3/2; x=25
Answers
Steve
just evaluate f'(x) at x=25
f'(x) = -5/2 x^(-1/2) + 3/2 x^(1/2)
= (-5/2)(1/5) + 3/2 (5)
= 7
f'(x) = -5/2 x^(-1/2) + 3/2 x^(1/2)
= (-5/2)(1/5) + 3/2 (5)
= 7