Question

Find the slope of the tangent to the curve y=2sqrt(x) at the point where x=a.

Find equations of the tangent lines at the points (1, 2) and (9, 6).
y = 2√x
y' = 1/√x
so at the point (a,2√a) the tangent line has equation
y-2√a = 1/√a (x-a)
so plug in whatever numbers you like

Related Questions

Consider the curve y^2+xy+x^2=15. What is dy/dx? Find the two points on the curve where y equals... --- Find the slope m of the tangent to the curve y = 4 + 4x^2 − 2x^3 at the point where x = a. --... find f'(x) find the slope of the graph of f a x=2 and x=4 find the equations of the tangent lines... Find the slope of a line tangent to the curve y=2x^2+4x at the point P(−3,6) by finding the limit of...