Question

Two people (from the 1950s!) sit on opposite sides of a uniform board of length L. One person, of mass m1 = 50.0 kg, sits at a point 1.90 m to the left of the fulcrum. The fulcrum is located at the center of the board. The other person, of mass 45.0 kg, sits at a point a distance x2 to the right of the fulcrum.


Calculate the value of x2 required for the system to be in rotational equilibrium. Make sure to enter units along with your numerical value, which should have 3 significant figures.

Answer 1

to balance,

m1 x1 = m2 x2
so,
(50.0)(1.90) = (45.0)(x2)
cinchy, right?

Answer 2

thank you so much !!