Question

If 0.200mol of nitrogen gas and 0.200mol of oxygen gas react, what is the limiting reactant?
N2(g)+O2(g)→2NO(g)

How many moles of NO are produced according to the equation?

Please show how to perform this equation with the answer please.

Answer 1

Here is how you do you it but you will need to go through and recalculate because I will do estimates only.

N2 + O2 ==> 2NO
Convert mols NH2 to mols NO using the coefficients in the balanced equation.
Thats 0.2 mol N2 x (2 mols NO/1 mol N2) = 0.2 x 2/1 = 0.4

Do the same with mols O2 to mols NO. That's 0.2 mols O2 x ( 2 mol NO/1 mol O2) = 0.2 x 2/1 = 0.4

There is no limiting reagent; both N2 and O2 react completely to form 0.4 mols NO.

Answer 2

How do I figure out the 2nd part? How many moles of NO are produced according to the equation?

I have watched several videos and I still don't understand this concept.

Answer 3

Re-read my response. Read it completely. Read it carefully. I told you how many mols NO were formed.

Answer 4

first answer is NO, and part B. is 2 mol