Question

If 0.500 mol of nitrogen gas occupies a volume of 11.0 L at 0°C, what volume will 2.15 mol of nitrogen gas occupy at the same temperature and pressure?
Use PV = nRT and solve for P for the first set, then use PV = nRT using P obtained from the first calculation and solve for V.
V = nRT/P .
Note that volume (V) is proportional to the number of moles, n.

So there would be 2.15/0.500 = 4.3 times as much volume.
That would be 47.3 liters.

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