Asked by help!! me
What is the distance between Nicholas's school and the post office?
Nicholas's school is in quadrant 1 and is on 3,2
Nicholas's post office is in quadrant 3 and is on -2,-2
A. 6.4
B. 5.2
C. 3.6
D. 3.0
Is the answer C?
Thanks
Nicholas's school is in quadrant 1 and is on 3,2
Nicholas's post office is in quadrant 3 and is on -2,-2
A. 6.4
B. 5.2
C. 3.6
D. 3.0
Is the answer C?
Thanks
Answers
Answered by
Brady
No.
By using the Distance Formula:
d = √(x2 - x1)^2 + (y2 - y1)^2
d = √(3 -(-2))^2 + (2 -(-2))^2
d = √(5)^2 + (4)^2
d = √25 + 16
d = √41
d = 6.4031242374328486864882176746218
So, I would think A to be the answer.
I hope this helps! :)
By using the Distance Formula:
d = √(x2 - x1)^2 + (y2 - y1)^2
d = √(3 -(-2))^2 + (2 -(-2))^2
d = √(5)^2 + (4)^2
d = √25 + 16
d = √41
d = 6.4031242374328486864882176746218
So, I would think A to be the answer.
I hope this helps! :)
Answered by
help!! me
I just need help with one more
Answered by
Brady
I finished doing it about 20 minutes to a half hour ago from what I am posting right now. I finally got the hang of the distance formula as well.
Answered by
Adolf, Hitler
Gas em
Answered by
kaliyah
thx you so much
Answered by
Student
D
D
B
A
D
D
B
A
D
Answered by
Anonymous
Thank you student
Answered by
NO CAP ITS TRUE
Thx student
Answered by
Yun91mp5tr
Student is still correct for connexus in 2021.
Answered by
k <3
student is correct ! thank you <33
Answered by
Lgbtq+ rights
I'm valid and so are @Students answers are.
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