Asked by Sean
A 1.0-kg cart and a 0.50-kg cart sit at different positions on a low-friction track. You push on the 1.0-kg cart with a constant 2.5-N force for 0.15m . You then remove your hand, and the cart slides 0.35 m and strikes the 0.50-kg cart.
By what amount does your force change the kinetic energy of the system's center of mass?
This is the third part of a question, If it helps part 1 found a work of 0.375 J and part two found a change in center of mass by .1 meters. I thought that the change in K would be 0.375 J because work equals change in K but it doesnt seem to be correct, I also solved for it and got that it should be 0.375 J.
By what amount does your force change the kinetic energy of the system's center of mass?
This is the third part of a question, If it helps part 1 found a work of 0.375 J and part two found a change in center of mass by .1 meters. I thought that the change in K would be 0.375 J because work equals change in K but it doesnt seem to be correct, I also solved for it and got that it should be 0.375 J.
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