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What is the pH of a solution prepared by mixing 150 mL of 0.1M HCl with 300mL of 0.1M sodium acetate (NaOAC) and diluting the mixture of 1L? PKa of acetic acid is 4.76. and give solution

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HCl = 150 x 0.1 = 15 millimols
NaOAc = 300 x 0.1 = 30 millimols.
pH = pKa + log (base)/(acid)
Substitute and solve for pH

4.77

4.77

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