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Maina john
What is the pH of a solution prepared by mixing 150 mL of 0.1M HCl with 300mL of 0.1M sodium acetate (NaOAC) and diluting the mixture of 1L? PKa of acetic acid is 4.76. and give solution
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Answered by
DrBob222
HCl = 150 x 0.1 = 15 millimols
NaOAc = 300 x 0.1 = 30 millimols.
pH = pKa + log (base)/(acid)
Substitute and solve for pH
Answered by
many
4.77
Answered by
Graventy
4.77
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