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how many grams of NH3 can be produced from 4.35moles of N2 and excess H2
1 answer
3H2 + N2 ==> 2NH3
4.35 mols N2 x ((2 mols NH3/1 mol N2) = 4.35 x 2 = ?
g NH3 = mols NH3 x molar mass NH3