how many grams of NH3 can be produced from 4.35moles of N2 and excess H2

1 answer

3H2 + N2 ==> 2NH3

4.35 mols N2 x ((2 mols NH3/1 mol N2) = 4.35 x 2 = ?
g NH3 = mols NH3 x molar mass NH3