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A golfer hits a shot to a green that is elevated 3 m above the point where the ball is struck. The ball leaves the club at a sp...Asked by Tami
A golfer hits a shot to a green that is elevated 3.10 m above the point where the ball is struck. The ball leaves the club at a speed of 19.4 m/s at an angle of 33.0˚ above the horizontal. It rises to its maximum height and then falls down to the green. Ignoring air resistance, find the speed of the ball just before it lands.
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Answered by
bobpursley
initial KE+initial PE=finalKE+finalPE
1/2 m 19.4^2 + 0 =1/2 m v^2 +mg*3.10
m divides out, solve for v
1/2 m 19.4^2 + 0 =1/2 m v^2 +mg*3.10
m divides out, solve for v
Answered by
Tami
i can't figure that out i got the wrong answer
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