Asked by joy
A golfer hits his approach shot at an angle of
θ = 52.8°,
giving the ball an initial speed of
v0 = 37.0 m/s
(see figure below). The ball lands on the elevated green,
yf = 5.3 m
above the initial position near the hole, and stops immediately.
θ = 52.8°,
giving the ball an initial speed of
v0 = 37.0 m/s
(see figure below). The ball lands on the elevated green,
yf = 5.3 m
above the initial position near the hole, and stops immediately.
Answers
Answered by
joy
please delete this question. this the wrong incomplete one.
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